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Find an equation of the plane.

The plane through the point $ (1, -1, -1) $ and parallel to the plane $ 5x - y - z = 6 $

$5 x-y-z=7$

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So the question is taken from victor's and Director of space. And the question is find the equation of plane passing to the point, my one minus one minus one and Pegler to the plane five weeks minus by minus that is equal to six. So the plane passing to the .1 -1 -1 and these spectacular to the plane five x minus y minus Z is equal to six. Okay, so we can write that equation of plain passing to 1 -1 -1 and is feculent to the plane five weeks -8 -8 is equal to six. Can be oh you don't know us five X minus y minus zero plus. Lambda is equal to zero. We can evaluate the value of lambda by substituting the value of X, Y, Z. And x Y Z is one minus one minus one since the plane passing through this point. So that will be five plus one plus one plus lambda is equal to zero. So from here the equation of plane will be by taking λ is equal to -7. So equation of plane will be five weeks minus y minus said Is equal to seven, which is the required equation of the plane. Hope this clears your doubt and thank you